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An ideal inductor of `(1//pi)` is connected in series with a `300gamma` resistor If a `20V.200H_(z)` ac source is connected across the combination the phase difference between the voltage and the current is .A. `tan^(-5)/(4)`B. `ta n-^(1)4/5`C. `ta n-^(1)3/4`D. `ta n-^(1)4/3` |
Answer» Correct Answer - D `f = 200 Hz , omega = 2pi f = 400 pi rad//sec` `X_(L) = omegaL = 400 pi xx (1)/(pi) = 400 Omega` `tan phi = X_(l)/R = (400)/(300) implies phi =tan^(-1) ((4)/(3))` . |
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