InterviewSolution
Saved Bookmarks
| 1. |
An ideal monoatomic gas undergoes a process in which its internal energy U and density `rho` vary as `Urho`= constant. The ratio of change in internal energy and the work done by the gas isA. (a) `3/2`B. (b) `2/3`C. (c) `1/3`D. (d) `3/5` |
|
Answer» Correct Answer - A `Urho=` constant `:.` `T=(1/V)=const ant` or `TpropV` `:.` `p=const ant` `(DeltaU)/(W)=(DeltaU)/(Q-DeltaU)` `=(nC_VDeltaT)/(nC_pDeltaT-nC_VDeltaT)` `=(1)/(gamma-1)=(1)/(5/3-1)=3/2` |
|