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An ideal refrigerator has a freezer at a temperature of `-13^(@)C`. The coefficient of performance of the engine is `5`. The temperature of the air (to which heat is rejected) will beA. `325^(@)C`B. `325 K`C. `39^(@)C`D. `320^(@)C` |
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Answer» Correct Answer - C Coefficient of performance `K = (T_2)/(T_(1)-T_(2)) implies 5=((273-13))/(T_(1)-(273-13)) = (260)/(T_(1)-260)` `= 5T_(1)-1300=260implies 5T_(1) = 1560` `implies T_(1)=312K rarr 39^@C`. |
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