1.

An ideally efficient transformer has a primary power input of 10 kW. The secondary current when the transformer is on load is 25 ampere. If the primary to secondary turns ratio is 8:1, then the potential difference applied to the primary coil is

Answer»

`(10^(4)XX8^(2))/(25)V`
`(10^(4)xx8)/(25)V`
`(10^(4))/(25xx8^(2))V`
`(10^(4))/(25xx8)V`

Solution :Input power = output power `= 10^(4)` W
`therefore e_(s)i_(s)=10^(4)rArr e_(s)=(10^(4))/(25)`
`therefore (e_(s))/(e_(p))=(n_(s))/(n_(p))=(1)/(8)rArr e_(s)xx8=e_(p)` or `e_(p)=(10^(4)xx8)/(25)V`


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