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| 1. |
An inductance of 1 mH, a condenser of 10 muF and a resistance of 50 Omega are connected in series. The reactances of inductors and condensers are same. What will be the reactance of either of them ? |
| Answer» <html><body><p>`5 Omega`<br/>`3 Omega`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/7omega-1921559" style="font-weight:bold;" target="_blank" title="Click to know more about 7OMEGA">7OMEGA</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> Omega`</p>Solution :Here L=1mH = `1xx10^(-3)` H <br/>`C=10 muF =10xx10^(-6)`F <br/> `R=50 Omega "" <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>=10^4` rad/s <br/> `X_L=X_C` and `X_L=omegaL` <br/> `=10^4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 1xx10^(-3)` <br/>`omegaL=1/(omegaC)` <br/>`therefore X_L=10Omega` <br/> `therefore omega^2=1/(<a href="https://interviewquestions.tuteehub.com/tag/lc-536651" style="font-weight:bold;" target="_blank" title="Click to know more about LC">LC</a>) "" X_C=1/(OmegaC)` <br/> `=1/(1xx10^(-3)xx10xx10^(-6)) "" 1/(10^4xx10xx10^(-6))` <br/> `=10^8` <br/> `therefore X_C=10 Omega`</body></html> | |