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An inductance of `1mH` a condenser of `0.5` henry and capacitance of `10xx10^(-6)F` are connected in series through `50Hz` AC supply, then impedence isA. `100 Omega`B. `30 Omega`C. `3.2 Omega`D. `10 Omega` |
Answer» Correct Answer - D Given `omegaL=1/(omegaC)implies omega^(2)=1/(LC)` or `omega=1/(sqrt(10^(-3)xx10xx10^(-6)))=1/(sqrt(10^(-8)))=10^(4)` `X_(L)=omega L =10^(4)xx10^(-3)=10Omega` |
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