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An inductor 200 mH, a capacitor C and a resistor 10 ohm are connected in series with a 100 V, 50 s^(-1) a.c. source. If the current and voltage are in phase with each other, calculate the capacitance of the capacitor.

Answer»

Solution :Here, L = 200 mH= 0.2 H, `V_(rms) = 100 V, v= 50 s^(-1)` or `omega = 2PI v = 2 XX 3.14 xx 50 = 314 rad s^(-1)`
As V and I are in phase, hence `X_(L) = X_(C)`
`rArr C = 1/(L omega^(2)) = 1/(2 xx (314)^(2)) = 5.07 xx 10^(-5) F = 50.7 muF`.


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