InterviewSolution
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InterviewSolution
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An inductor `20xx10^(-3)` a capacitor `100(mu)F` and a resistor `50 Omega` are connected in series across a source of emf `V=10 sin 314 t`. If resistance is removed from the circuit and the value of inductance is doubled, the variation of current with time in the new circuit is |
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Answer» Correct Answer - `951.52 J;0.52 cos 314 t` Given that `L=20xx10^(-3) H` `C=100xx10^(-6) F` `R=50 Omega , omega=314` `V=10 sin 314 t , Deltat=20xx60` second (i)`DeltaH=I_(rms)^(2)R(Deltat)=(V_(0)/(sqrt2 Z))^(2) RxxDeltat` here `z=sqrt(R^(2)+(omegaL-1/(omegac))^(2))=sqrt((50)^(2)+(6.28-31.8)^(2))=56.15 Omega` (ii)`I=I_(0)sin (314t+pi//2)` where `I_(0)=V_(0)/((omega(2L)-1/(omegac)))` |
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