Saved Bookmarks
| 1. |
An inductor coil is connected to a 10 V battery and in steady state, a current of 10 A is found to flow through it. Now this inductor coil is connected in series with a capacitor , and this combination is connected across AC supply of rms voltage 12 V. it is found that current flowing in the circuit is in the same phase with the voltage. Find the rms current flowing through the circuit. |
|
Answer» Solution :We can understand that RESISTANCE is also ASSOCIATED with the inductor coil and the same can be calculated by applying ohm.s law in case of DC circuit given to us. V = IR `rArr 10 = 10 xx R rArr R = 1 Omega`. If Z is the net impedance in the circuit, then rms current can be written as `I_(rms) = (V_(rms))/(Z)` . In this QUESTION, it is given that current is in the same PHASE with the voltage , and this is possible only when net reactance of the circuit is zero. We know that in series LCR circuit net neactance may be zero when reactance of inductor and capacitor is equal . In such a SITUATION, net impedance of the circuit becomes equal ot resistance of the circuit. Hence, Z = R = 1 `Omega`. Hence, rms current of this circuit can be written as ` I_(rms) - (V_(rms))/(Z) = (12)/(1) = 12 `A |
|