1.

An inductor of `1` henry is connected across a `220 v, 50 Hz` supply. The peak value of the current is approximately.

Answer» `i_(0) = (E_(0))/(X_(L)) = (sqrt(2)E_("rms"))/(omega L) = (sqrt(2)E_("rms"))/(2 pi f L) = (sqrt(2)(220))/(2 pi xx 50 xx 1) = 0.99 A`


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