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An inductor of 3H is connected to a battery of emf 6V through a resistance of 100Omega . Calculate the time constant. What will be the maximum value of current in the circuit? |
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Answer» Solution :Given that L = 3H.E=6V,R=100`OMEGA` Time constant `tau_L = L/R = 3/100 = 0.03`sec MAXIMUM CURRENT`I_0 = E/R =6/100 ` amp = 0.06 amp |
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