1.

An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency omega. The power dissipated in the circuit is

Answer»

`(V)/(R^2+ OMEGA^2 L^2)`
`(R^2+ omega^2 L^2)/( V)`
`(V^2 R)/( sqrt(R^2+omega^2L^2))`
`(V^2 R)/( R^2 + omega^2 L^2)`

SOLUTION :RL CIRCUIT
` P=V _(" RMS")I_("rms") cos phi,cosphi= (R )/( Z ) = V(V )/(Z ), (R )/(Z)= (V^2 R)/(sqrt(R^2 =( Omega L)^2)))`


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