An inductor of inductance `L` and ressistor of resistance `R` are joined in series and connected by a source of frequency `omega`. Power dissipated in the circuit isA. `((R^(2)+omega^(2)L^(2)))/V`B. `(V^(2)R)/((R^(2)+omega^(2)L^(2)))`C. `V/((R^(2)+omega^(2)L^(2)))`D. `(sqrt(R^(2)+omega^(2)L^(2)))/(V^(2))`

An inductor of inductance `L` and ressistor of resistance `R` are join

1.	An inductor of inductance `L` and ressistor of resistance `R` are joined in series and connected by a source of frequency `omega`. Power dissipated in the circuit isA. `((R^(2)+omega^(2)L^(2)))/V`B. `(V^(2)R)/((R^(2)+omega^(2)L^(2)))`C. `V/((R^(2)+omega^(2)L^(2)))`D. `(sqrt(R^(2)+omega^(2)L^(2)))/(V^(2))`
Answer» Correct Answer - B `P= Vi cos varphi=V(V/Z)(R/Z)=(V^(2)R)/(Z^(2))=(V^(2)R)/((R^(2)+omega^(2)L^(2)))`

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