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An inductor of reactance 1 Omegaand a resistor of 2Omega are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit is |
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Answer» 8 W `lt P gt =V_"rms" I_"rms" cos phi` …(1) but `I_(rms)=V_(rms)/Z` but `Z=sqrt(R^2+X_L^2)=sqrt((2)^2 + (1)^2)=sqrt5Omega` `therefore I_(rms)=V_(rms)/Z=6/sqrt5`A ….(2) cos `phi=R/Z=2/sqrt5`...(3) Putting the values of equation (2) and (3) in equation (1), `lt P gt =6xx6/sqrt5xx2/sqrt5` `=72/5` `therefore lt P gt` =14.4 W |
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