An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field due to this current at the point M is B_(1). Now, another infinitely long straight conductor QS is connected at Q so that the current is I//2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now B_(2) = 4 mT. Find the value of B_(1) ("in" mT).

An infinitely long conductor PQR is bent to form a right angle as show

1.	An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field due to this current at the point M is B_(1). Now, another infinitely long straight conductor QS is connected at Q so that the current is I//2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now B_(2) = 4 mT. Find the value of B_(1) ("in" mT).
Answer» Solution :`B_(1)=(mu_(0)I)/(4 pi R)` `B_(2)=(mu_(0)I)/(4pi R) + (mu_(0)(I/2))/(4 pi R) = 3/4 (mu_(0)I)/(4 pi R)` `(B_1)/(B_2) = 3/4 implies B_(2)= 3/4 B_(2) = 3/2 xx 4 = 3 MT`.

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