InterviewSolution
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InterviewSolution
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An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume `V_1` and contains ideal gas at pressure `P_1` and temperature `T_1`.The other chamber has volume `V_2` and contains ideal gas at pressure `P_2` and temperature `T_2`. If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will beA. `(T_(1)T_(2) (P_(1)V_(1) + P_(2)V_(2)))/(P_(1) V_(1) T_(2) + P_(2)V_(2)T_(1))`B. `(P_(1) V_(1)T_(1) + P_(2)V_(2)T_(2))/(P_(1)V_(1) +P_(2)V_(2))`C. `(P_(1) V_(1)T_(2) + P_(2)V_(2)T_(1))/(P_(1)V_(1) +P_(2)V_(2))`D. `(T_(1)T_(2) (P_(1)V_(1) + P_(2)V_(2)))/(P_(1) V_(1) T_(1) + P_(2)V_(2)T_(2))` |
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Answer» Correct Answer - A `P_(1)V_(1)T_(1) P_(2), V_(2), T_(2)` As container is insulated `q = 0 ` `q_(1) + q_(2) = 0` `n_(1)C_(m) (T- T_(1)) + n_(2) C_(m) (T - T_(2)) = 0` `T =(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+ n_(2))=((P_(1)V_(1) + P_(2)V_(2)) T_(1)T_(2))/(P_(1)V_(1)T_(2) + P_(2)V_(2)T_(1))` |
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