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An integrating factor of the differential equation `ylogy(dx)/(dy)+x-logy=0`, isA. `log(logy)`B. `logy`C. `(1)/(logy)`D. `(1)/(log(logy))` |
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Answer» Correct Answer - B We have, `(dx)/(dy)+(1)/(y log y)x=(1)/(y)` `"I.F."=e^(int(1)/(y log y))dy=e^(log(logy))=logy` |
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