InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
An iron block of mass m = 500 kg is kept at the back of a truck moving at a speed v_(0)=90km h^(-1). The driver applies the brakes and shows down to a speed of v=54km h^(-1) in 10s. What constant force acts on the block during this time if the block does not slide on the truck-bed? |
|
Answer» Solution :The acceleration, `a=(v-v_(0))/(t)` `=(54 km h^(-1)-90kmh^(-1))/(10s)` `=(15ms^(-1)-25ms^(-1))/(10s)` `=-1m//s^(2)` or, Force F = ma `=500kg (-1 ms^(-2))` `=-500N` -ve sign INDICATES that the force ACTS opposite to the VELOCITY of the block. The magnitude of force is 500 N. |
|