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An iron tyre is to be fitted onto a wooden wheel 1.0 m in diameter. The diameter of the tyre is 6 mm smaller than that of wheel the tyre should be heated so that its temperature increases by a minimum of (coefficient of volume expansion of iron is `3.6xx10^-5//^@C`)A. `167^@C`B. `334^@C`C. `500^@C`D. `1000^@C` |
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Answer» Correct Answer - C Initial diameter of tyre`=(100-6)mm`,`=994mm`, so initial radius of tyre `R=(994)/(2)=497mm` and change in diameter `DeltaD=6mm`, so `DeltaR=(6)/(2)=3mm` Given that after increasing temperature by `DeltaT` tyre will fit onto wheel Increment in the length (circumference) of the iron tyre `DeltaL=LxxalphaxxDeltaT=Lxx(gamma)/(3)xxDeltaT` `(Asalpha=(gamma)/(3))` `implies2piR=2piR((gamma)/(3))DeltaT` `impliesDeltaT=(3)/(gamma)(DeltaR)/(R )=(3xx3)/(3.6xx10^-5xx497)` [As `Delta R=3` mm and `R = 497` mm] `impliesDelta=500^@C` |
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