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An isolated particle of mass m is moving in horizontal plane along the x - axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and (3m)/4. At an instant the smaller fragment is y=+15 cm . The larger fragment, at this instant is at |
Answer» Solution :As `vecF_(y)=0, DeltavecP_(y)=0, vecP_(y) = vecP_(yf)`  `vecP_(yi) =0, therefore m_(i) vecV_(y) + m_(2) vecV_(y2)=0, m_(1)vecy_(1) =-m_(2)vecy_(2)` `y_(2) =-(m/4 XX 15)/(3m//4),y_(2) = -5 cm` |
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