An isolated particle of mass m is moving in horizontal plane along the x - axis at a certain height above the ground. It suddenly explodes into two framents of masses (m)/(4) and (3m)/(4). At an instant the smaller frament is at y=+15 cm. The larger fragment, at this instant is at

An isolated particle of mass m is moving in horizontal plane along the

1.	An isolated particle of mass m is moving in horizontal plane along the x - axis at a certain height above the ground. It suddenly explodes into two framents of masses (m)/(4) and (3m)/(4). At an instant the smaller frament is at y=+15 cm. The larger fragment, at this instant is at
Answer» <P> Solution :As `vec(F)_(y)=0 "" Delta vec(P)_(y)=0 vec(P)_(y1)=vec(P)_(YF)` `vec(P)_(YI)=0 THEREFORE m_(1)vec(V)_(y1)+m_(2)vec(V)_(y2)=0, m_(1)vec(y)_(1)=-m_(2)vec(y)_(2)` `y_(2)=-((cancel(m))/(4)xx15)/((3cancel(m))/(4))y_(2)=-5cm`

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An isolated particle of mass m is moving in horizontal plane along the x - axis at a certain height above the ground. It suddenly explodes into two framents of masses (m)/(4) and (3m)/(4). At an instant the smaller frament is at y=+15 cm. The larger fragment, at this instant is at

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