1.

An isosceles right angled current carrying loop PQR is placed in a uniform magnetic field vecB pointing along PR. If the magnetic force acting on the arm PQ is F, then the magnetic force which acts on the arm QR will be

Answer»

`F`
`F/(sqrt2)`
`sqrt2F`
`-F`

Solution :(d)-F
[Hint : Net force on entire loop PQR is zero and force on area RP is ALSO zero because here current is ANTIPARALLEL to magnetic field B.
`rArrF_(PQ)+F_(QR)=0` or `F_(QR)=-F_(PQ)=-F`]


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