An `L-C-R` series circuit with `100Omega` resistance is connected to an `AC` source of `200V` and angular frequency `300rad//s`. When only the capacitance is removed, the current lags behind the voltage by `60^@`. When only the inductance is removed the current leads the voltage by `60^@`. Calculate the current and the power dissipated in the `L-C-R` circuitA. 50 WB. 100 WC. 200 WD. 400 W

An `L-C-R` series circuit with `100Omega` resistance is connected to a

1.	An `L-C-R` series circuit with `100Omega` resistance is connected to an `AC` source of `200V` and angular frequency `300rad//s`. When only the capacitance is removed, the current lags behind the voltage by `60^@`. When only the inductance is removed the current leads the voltage by `60^@`. Calculate the current and the power dissipated in the `L-C-R` circuitA. 50 WB. 100 WC. 200 WD. 400 W
Answer» Correct Answer - D Phase angle , tan`phi` = `X_L`/R = `X_C`/R `implies` tan`60^(@)` = `X_L`/R = `X_C`/R `implies` `X_L` = `X_C` = `sqrt 3` i.e., Z = `sqrt R^(2) + (sqrt 3 R - sqrt 3 R)^(2) ` `implies` Z = R So, avaerage power , P = `V^(2)`/R = `200 xx 200 `/ 100 = 400 W

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