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An LC circuit contains a 20 mH inductor and `25 mu F` capacitor with an initial charge of 5 mC. The total energy stored in the circuit initially isA. 5 JB. `0.5 J`C. 50 JD. 500 J |
Answer» Correct Answer - B Here, `C = 25 mu F = 25xx10^(-6)F`, `L=20 mH=20xx10^(-3)H, q_(0)=5 mC=5xx10^(-3)C` `therefore` Total energy stored in the circuit initially is `U = (q_(0)^(2))/(2C)=((5xx10^(-3))^(2))/(2xx25xx10^(-6))=(25xx10^(-6))/(2xx25xx10^(-6))=(1)/(2)=0.5 J` |
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