InterviewSolution
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InterviewSolution
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An LCR series circuit consists of a resistance of a `10 Omega` a capacitance of reactance `60 Omega` and an inductor coil The circuit is found to resonate when put across a `300 V ,100 ` Hz supply The inductance of the coil is `(taken pi =3)` .A. 0.1 HB. 0.01 HC. 0.2 HD. 0.02 H |
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Answer» Correct Answer - A Angular velocity, `omega_o = 2pinu= 2pi xx 100` `omega_o = 2 xx 3 xx 100` = `600 rad s^(-1)` [since`pi` = 3] Further , `omega_o = 1 / sqrt LC` …..(i) Also, `X_C = 1 / COmega_o = 60 Omega` `implies C = 1 / omega_(o) xx 60 = 1 / 600 xx 60impliesC = 1 / 36 xx 10^(3)` F so, put values in Eq(i), we get `600 = 1 / sqrt(L(1/36 xx 10^(3)))` `implies 36 x 10^(4) = 36 xx 10^(3) / L implies 36 xx 10^(3) / 36 xx 10^(4) = 1/10` = 0.1 H |
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