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An LCR series circuit with L =0.5H, C=10xx10^(-6) F, R=100 Omegais connected to an A.C. source of frequency of 50 Hz. The impedance of the circuit is ……. |
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Answer» 1.8765 `Omega` `|Z|=SQRT(R^2+(omegaL-1/(omegaC))^2)` `=sqrt((100)^2+[314xx0.5-1/(314xx10^(-5))]^2)` `|Z|=sqrt(10^4+[157-50000/147]^2)` `THEREFORE |Z|=189.6 Omega` |
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