1.

An LCR series circuit with L =0.5H, C=10xx10^(-6) F, R=100 Omegais connected to an A.C. source of frequency of 50 Hz. The impedance of the circuit is …….

Answer»

1.8765 `Omega`
18.76 `Omega`
189.6 `Omega`
101.3 `Omega`

SOLUTION :`omega=2pif=2xx3.14xx50`=314 rad/sec
`|Z|=SQRT(R^2+(omegaL-1/(omegaC))^2)`
`=sqrt((100)^2+[314xx0.5-1/(314xx10^(-5))]^2)`
`|Z|=sqrt(10^4+[157-50000/147]^2)`
`THEREFORE |Z|=189.6 Omega`


Discussion

No Comment Found

Related InterviewSolutions