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An LCRseries circuit has a resistance of 25 Omega and a reactance of 93.25 Omega. If the reactance is capacitive, what is the phase angle between the current and applied emf ? Does the applied emf lag behind or lead the current ? |
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Answer» Solution :Date : ` R = 25 Omega, |X_(L) - X_(C)| = 93.25 Omega` (capacitive) Since the reactance is capacitive , ` X_(C) gt X_(L)` The phase angle ` phi ` is geven by ` tan phi = (X_(L) - X_(C))/R = (-93.25)/25` ` = - 3.730` ` :. Phi = tan ^(-1) (- 3.730)` ` = -75^(@)` `{:(log 93.25,," "1.9696),(log 25,,ul(-1.3979)),(,," "0.5717):}` AL ` 0.5717 = 3.730` i.e. the applied emf lags BEHIND the current by ` 75^(@)`. |
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