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an object 2 cm tall placed at 40 cm from a convex mirror if it has a focal length of 15 CM then find nature size and position of image​

Answer» JECT distance) = -15 as u is always negativeF = -10 (as it is always negative for concave miror and lens )1/F =1/v + 1/u-1/10 = 1/v + (-1/15)-1/10 +1/15 =v-3+2/30 =vV=-30cmHi/Ho = - V/UHi /2 = -(-30/15)Hi =-30×2÷15Hi =-4cm (Real and inverted)


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