1.

An object attached to a light spring oscillates in S.H.M. on horizontal smooth surface. The ratio of maximum P.E. to maximum K.E. is :

Answer»

`1//2`
2
1
`sqrt(3)//2`

Solution :MAX. P.E. = Max. K.E. `=(1)/(2)m omega^(2)R^(2)`
`:. ((P.E.)_("max"))/((K.E.)_("max"))=1`
`:.` Correct choice is ( c ).


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