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An object falls from a bridge which is 45 m above the water,It falls directly into a smaal row-boat moving with contant velocity that was 12m from the point of impact when the object was released.What was the speed of the boat? |
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Answer» Solution :VELOCITY of boat=`V=(s)/(t)`,Here,s=12m t=time of fall of OBJECT from bridge `sqrt(2h)/(g)=sqrt(2xx45)/(10)=3s therefore V=(12)/(3)=4ms^(-1)` |
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