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An object is 5 m to the left of a flat screen. A converging lens for which the focal length is 0.8m is placed between object and screen.How do the two images differ from each other? |
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Answer» Solution :`m=(v)/(U ) ` ` therefore m_1= ((5-4))/((-4)) = -0.25 and m_2 =((5-1))/((-1)) =-4.00` Hence, both the images are real and inverted, the FIRST has magnification -0.25 and the SECOND -4.00. |
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