1.

An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by 10 cm. The size of the images in two situtation are in the ratio 3 : 2. What is the distance between the screen and the object?

Answer»

124.5 CM
144.5 cm
65.0 cm
99.0 cm

Solution :Given, ratio of magnification of image which is FORMED by two postion of lens.

`implies (m_1)/(m_2) = ((D + d)/(D - d))^(2)`
`implies 3/2 = ((D + 10)/(D - 10))^(2)`
`3(D - 10)^2 = 2 (D + 10)^2`
`3(D^2 + 100 - 20D) = 2(D^2 + 20 D + 100)`
`D^2 - 100 D + 100 = 0`
`D = 99 cm`


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