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An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by 10 cm. The size of the images in two situations are in the ratio 3:2. What is the distance between the screen and the object ? |
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Answer» 124.5 CM `(I_(1))/(I_(2))=(3)/(2)` `(I_(1))/(I_(2))=((d+x)/(d-x))^(2)` `(3)/(2)=((d+x)^(2))/(d-x)^(2)` `(3)/(2)=(d^(2)+x^(2)+2xd)/(d^(2)+x^(2)-2xd)` `3d^(2)+3X^(2)-6xd=2d^(2)+2x^(2)+2x^(2)+4xd` `d^(2)+x^(2)-10xd=0` `d^(2)-100d+100=0` `d=99cm` |
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