1.

An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by 10 cm. The size of the images in two situations are in the ratio 3:2. What is the distance between the screen and the object ?

Answer»

124.5 CM
144.5 cm
65.0 cm
99.0 cm

Solution :LET the distnace between the object and SCREEN be d and GAP of lens is `x=10cm`
`(I_(1))/(I_(2))=(3)/(2)`
`(I_(1))/(I_(2))=((d+x)/(d-x))^(2)`
`(3)/(2)=((d+x)^(2))/(d-x)^(2)`
`(3)/(2)=(d^(2)+x^(2)+2xd)/(d^(2)+x^(2)-2xd)`
`3d^(2)+3X^(2)-6xd=2d^(2)+2x^(2)+2x^(2)+4xd`
`d^(2)+x^(2)-10xd=0`
`d^(2)-100d+100=0`
`d=99cm`


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