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An object is placed 12 cm to the left of a diverging lens of focal length -6.0 cm. A converging lens of focal length of 12.0 cm is placed at a distance d to the right of the diverging lens. Find the distance d that corresponds to a final image at infinity. |
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Answer» Solution :Applyinglensformula` (1)/(V)- (1)/(u ) = (1)/(f)` twice we have ` (1)/(v_1) - (1 )/(-12) =(1)/(-6)` `impliesv_1=- 4 cmand (1)/(oo) - (1)/(v_1 -d) = (1)/(12) impliesd= 8 CM` |
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