An object is placed 21 cm in fron of a concave mirror of radis of curvature 20 cm.A glass slab of thicknes 3 cm and refractive index 1.5 is palced close to the mirror in the space between the object and the mirror. Find the position of the final image fromed. The distance of the nearer surface of the slab from the mirror is 10 cm.

An object is placed 21 cm in fron of a concave mirror of radis of curv

1.	An object is placed 21 cm in fron of a concave mirror of radis of curvature 20 cm.A glass slab of thicknes 3 cm and refractive index 1.5 is palced close to the mirror in the space between the object and the mirror. Find the position of the final image fromed. The distance of the nearer surface of the slab from the mirror is 10 cm.
Answer» <P> Solution : Shift by GLASS slab `=3(1-(1)/(3//2))=1cm` The MIRROR will be shifted towards slab by `1cm`. Distance of object O from VIRTUAL mirror `A^'P^'B^'=20cm`. Image of O is formed on O itself by `A^'P^'B^'` (since O is at centre of curvature of mirror `A^'P^'B^'`. Distance of image from original mirror APB is `21cm`. In fact, object and image COINCIDE.

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