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An object is placed at 21 cm in front of a concave mirror of radius of a curvature 10 cm. A glass slab of thickness 3 cm and u 15 is then placed close to the mirror in the space between the object and the mirror. The position of final image formed is |
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Answer» `-3.94cm` `(mu-1)t=(1.5-1)3 cm` =1.5 cm `U'=-(21+1.5)cm` or u'=-22.5 cm Now, `1/(-22.5)+1/V=1/(-5)` or `1/v=1/22.5-1/5or1/v=(5-22.5)/(22.5xx5)` or `v=(22.5xx5)/17.5 or v=-6.43 cm` |
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