1.

An object is placed at 21 cm in front of a concave mirror of radius of a curvature 10 cm. A glass slab of thickness 3 cm and u 15 is then placed close to the mirror in the space between the object and the mirror. The position of final image formed is

Answer»

`-3.94cm`
4.3 cm
`-4.93`
3.94 cm

Solution :(c ) DUE to glass slab increase in PATH
`(mu-1)t=(1.5-1)3 cm`
=1.5 cm
`U'=-(21+1.5)cm`
or u'=-22.5 cm
Now, `1/(-22.5)+1/V=1/(-5)`
or `1/v=1/22.5-1/5or1/v=(5-22.5)/(22.5xx5)`
or `v=(22.5xx5)/17.5 or v=-6.43 cm`


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