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An object is placed at a distance of `f//2` from a convex lens. The image will beA. At one of the foci, virtual and double its sizeB. At `3f//2` , real and invertedC. At `2f, ` virtual and erectD. None of these |
Answer» Correct Answer - A `(1)/(f)=(1)/(v)+(1)/(u)``(` Given `u=(-f)/(2))` `implies(1)/(f)=( 1)/(v)+((1)/(f//2))implies(1)/(v)=(1)/(f)-(1)/(f)` `implies (1)/(v)=(-1)/(f)` and `m=(v)/(u)=(f)/(f//2)=2` So virtual at the focus and of double size. |
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