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An object is placed in front of a converging lens of focal length 10 cm and image formed is double the size of object. Then find out the position of object. |
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Answer» Solution :Case I : If the image FORMED is real `-h_(i)/h_(0)=2` `rArr v/u=-2 rArr v=-2u` `1/f=1/v-1/u` `rArr 1/10=-1/(2v)-1/u` `rArr 1/10=-3/(2u)` `rArr u=-15` CM Case II :If the image formed is virtual `h_(i)/h_(0)=2` `rArr v=2u` `1/f=1/v-1/u` `rArr 1/10=1/(2u)-1/u` `rArr 1/10=-1/(2u)` `rArr u=-5` cm |
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