InterviewSolution
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InterviewSolution
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An object is projected vertically upward from the surface of the earth at which above and below the surface acceleration due to gravity is the same. |
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Answer» Correct Answer - `h=(sqrt(5-1))/2 R` Let at height or depth `h` from the surface of earth acceleration due to gravity is same. `g_(d)=g_(h)` `g(1-h/R)=(gR^(2))/((R+h)^(2))implies((R-h))/R=(R^(2))/((R+h)^(2))` `(R-h)(R+h)^(2)=R^(3)` `(R-h)(R^(2)+h^(2)+2hR)=R^(3)` `R^(3)+Rh^(2)+2hR^(2)-hR^(2)-h^(3)-2h^(2)R=R^(3)` `h^(3)+h^(2)R-hR^(2)=0` `h^(2)+hR-R^(2)=0` `h=(-R+-sqrt(R^(2)+4R^(2)))/2impliesh=((sqrt(5)-1)R)/2` |
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