1.

An object is projected vertically upwards. It explodes at the topmost point of its trajectory into three identical fragments. One of the fragments comes straight down in time t_(1) while the other two lands at a time t_(2) after explosion. Height at which the explosion occurred is equal to

Answer»

`(g t_(1)t_(2)(t_(2)+3t_(1)))/(2(t_(1)+t_(2)))`
`(g t_(1)t_(2)^(2))/(2t_(3))`
`(g t_(1)t_(2)(t_(1)+2t_(2)))/(2(2t_(1)+t_(2)))`
`(g t_(1)t_(2)(2t_(1)+t_(2)))/(4(t_(1)+2t_(2)))`

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