An object is projected with velocity 20 m s^(-1) making an angle of 45° with horizontal. The equation for its trajectory is h = Ax - Bx^(2) , where h is the height and x the horizontal distance. The ratio of constants A : B

An object is projected with velocity 20 m s^(-1) making an angle of 45

1.	An object is projected with velocity 20 m s^(-1) making an angle of 45° with horizontal. The equation for its trajectory is h = Ax - Bx^(2) , where h is the height and x the horizontal distance. The ratio of constants A : B
Answer» `1:5` `5:1` `1:40` `40:1` SOLUTION :Here A=`tantheta` and `B=G/(2U^(2)cos^(2)THETA)` `:. A/B=(2u^(2)cos^(2)theta.tantheta)/g` `=(2xx400xx1/2)/10=40/1`

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An object is projected with velocity 20 m s^(-1) making an angle of 45° with horizontal. The equation for its trajectory is h = Ax - Bx^(2) , where h is the height and x the horizontal distance. The ratio of constants A : B

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