An object is projected with velocity 20 ms^(-1) making an angle of 45° with horizontal. The equation for its trajectory is h = Ax - Bx^(2) where h is the height and x the horizontal distance at any instant. The ratio of constant A:B is:

An object is projected with velocity 20 ms^(-1) making an angle of 45�

1.	An object is projected with velocity 20 ms^(-1) making an angle of 45° with horizontal. The equation for its trajectory is h = Ax - Bx^(2) where h is the height and x the horizontal distance at any instant. The ratio of constant A:B is:
Answer» `1:2` `5:1` `1:40` `40:1` SOLUTION :Compairing with EQUATION of trajectory, we get `A=tantheta` and `B=g/(2U^(2)cos^(2)theta)` `A/B=(2.u^(2)cos^(2)theta.tantheta)/g=(2xx400xx1/2)/10=40/1`

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An object is projected with velocity 20 ms^(-1) making an angle of 45° with horizontal. The equation for its trajectory is h = Ax - Bx^(2) where h is the height and x the horizontal distance at any instant. The ratio of constant A:B is:

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