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An object is thrown horizontally with an initial speed of 10 m//s. How far will it drop in 4 seconds ? |
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Answer» SOLUTION :The first step is to decide whether this is a horizontal question or a vertical question, since you must consider these motions separately. The question " How far will it drop ? " is a vertical question, so we'll USE the set of equations listed above under vertical motion. NEXT, " how far..? " implies that we will use the first of the vertical-motion equation, the one that gives vertical displacement, `DELTA y`. Since the object is thrown horizontally, there is no vertical component to its initial velocity vector `v_(0)`, that is , `v_(0_(y))=0`. So `Delta y= v_(0_(y)) t+(1)/(2)(-g)t^(2) to Delta y =(1)/(2)(-g)t^(2) ("because " v_(0_(y))=0)` `=(1)/(2)(-10)(4^(2))` `= -80 m`  The fact that `Delta y` is negative means that the displacement is down. Also, notice that the information given about `v_(0_(x))` is irrelevant to the question. |
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