InterviewSolution
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InterviewSolution
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An object is thrown vertically upwards and rises to a height of 13.07m. Calculate (i) the velocity with which the object was thrown upwards. (ii) the time taken by the object to reach the highest point. { take s=h(height) and a=g (acceleration due to gravity)} g=9.8m/s2 |
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Answer» (i) To FIND Initial VELOCITY (u) we Will use, => v = u + GT => 0 = 16 +(- 9.8) t => 0+16 = -9.8t => 16/-9.8 = t => 1.63s = t(ii) To find TIME , we will use => v²- u² = 2gs Now put values, => (0)² - u² = 2*-9.8*13.07 => u² = 256.172 => u = √256.172 => u = 16 |
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