An object moving with a speed of 6.25m s^(-1) , isdeceleratedat a rate given by(dv)/(dt)= - 2.5 sqrt(v), where v isthe instantaneousspeed.The time takenby the object to come to rest,would be

An object moving with a speed of 6.25m s^(-1) , isdeceleratedat a rate

1.	An object moving with a speed of 6.25m s^(-1) , isdeceleratedat a rate given by(dv)/(dt)= - 2.5 sqrt(v), where v isthe instantaneousspeed.The time takenby the object to come to rest,would be
Answer» 2s 4 s 8 s 1 s Solution :Given:` (dv)/(DT) = 2.5 sqrt(v) or (dv)/sqrtv = 2.5 dt ` INTEGRATING both SIDES within the given conditions, we GET `int_(6.25)^(0) (dv)/sqrtv=int_(0)^(t)-2.5 dt ` ` 2[sqrtv]_(6.25)^(0)=-2.5t or -2sqrt(6.25) = -2.5t or t =2s `

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An object moving with a speed of 6.25m s^(-1) , isdeceleratedat a rate given by(dv)/(dt)= - 2.5 sqrt(v), where v isthe instantaneousspeed.The time takenby the object to come to rest,would be

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