an object of 5 kg mass is placed on a cylindrical stand have a circular cross-section the radius of the base of a stand is 4 cm if the same object is placed on cyclinderial stand with radius of the base of a stand is 2 cm then pressure becomes

an object of 5 kg mass is placed on a cylindrical stand have a circula

1.	an object of 5 kg mass is placed on a cylindrical stand have a circular cross-section the radius of the base of a stand is 4 cm if the same object is placed on cyclinderial stand with radius of the base of a stand is 2 cm then pressure becomes
Answer» Case 1 :- Mass of object , m = 5 kg radius of base of cylindrical stand , r = 4cm = 0.04 m ∵ pressure = Force /base area Force = weight of body = mg = 5 × 10 = 50 N base area = πr² = π(0.04)² m² ∴ initial Pressure = 50N/π(0.04)² ------(1) Case 2 :- radius if base of cylindrical stand , r' = 2cm = 0.02m ∵pressure = force/base area Force = weight of body = mg = 50N Base area = πr'² = π (0.02)² m² ∴ final pressure = 50N/π(0.02)² ------(2) From equations (1) and (2), Initial pressure /final pressure = {50N/π (0.04)²}/{50N/π(0.02)²} = 1/4 initial pressure = final pressure/4 Or, final pressure = 4 × initial pressure