An object of mass 0.5 kg is tied to a string and revolved in a horizon

1.	An object of mass 0.5 kg is tied to a string and revolved in a horizontal circle of radius 1 m. If the breaking tension of the string is 50 N, what is the maximum speed the object can have?
Answer» Data : m = 0.5 kg, r = 1 m, F = 50 N The maximum centripetal force that can be applied is equal to the breaking tension. \(\therefore\) \(\frac{mv^2}r\) = F \(\therefore\) v = \(\sqrt{\frac{Fr}m}\) = \(\sqrt{\frac{50 \times1}{0.5}}\) = 10 m/s This is the maximum speed the object can have.

An object of mass 0.5 kg is tied to a string and revolved in a horizontal circle of radius 1 m. If the breaking tension of the string is 50 N, what is the maximum speed the object can have?

Answer»

Data : m = 0.5 kg, r = 1 m, F = 50 N The maximum centripetal force that can be applied is equal to the breaking tension.

\(\therefore\) \(\frac{mv^2}r\) = F

\(\therefore\) v = \(\sqrt{\frac{Fr}m}\) = \(\sqrt{\frac{50 \times1}{0.5}}\) = 10 m/s

This is the maximum speed the object can have.

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An object of mass 0.5 kg is tied to a string and revolved in a horizontal circle of radius 1 m. If the breaking tension of the string is 50 N, what is the maximum speed the object can have?

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