1.

An object of mass 0.5 kg, moving in a circular path of radius 0.25m, experiences a centripetal acceleration of constant magnitude 9 m//s^(2). What is the object's angular speed?

Answer»

`2.3rad//s`
4.5rad/s
6rad/s
12rad/s

Solution :By combining the equation for centripetal acceleration `a_(c)=V^(2)//r`, with `v=ROMEGA,` we find
`a_(c)=(v^(2))/(r)=((romega)^(2))/(r)=OMEGA^(2)r IMPLIES omega=sqrt((a_(c))/(r))=sqrt((9m//s^(2))/(0.25m))=6s^(-1)`


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