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An object of mass 40 kgand having velocity 4 ms^(-1)collides with another object of mass 60 kg. havingvelocity 2m s^(-1)The lossof kinetic energy when the collision is perfectlyineleastic is |
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Answer» SOLUTION :Here, ` m_(1) = 40 kg , u_(1) = 4 m s^(-1)` `m_(2) = 60 kg , u_(2) =m s^(-1)` Accordingto law of conservation of linear momentum,we get ` (m_(1) + m_(2))v = m_(1)u_(1) + m_(2)u_(2)` ` v = ( m_(1)u_(1)+m_(1)u_(2))/( m_(1)+m_(2)) = (40 xx 4 + 60 xx 2)/(40 + 60 )= 2.8 m s^(-1) ` Loss in KE = ` 1/2m_(1)u_(1)^(2) + 1/2 m_(2)u_(2)^(2) - 1/2 (m_(1) + m_(2))v^(2)` `1/2 [40 xx 16 + 60 xx 4 - 100 xx 2.8^(2)] = 48 J ` |
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