An object of mass M is tied to a string of l and revolve in a horizontal circle .If length is reduced by `l//2`, then period isA. `T//sqrt2`B. `2sqrt2 T`C. `T//4`D. `2 T`

An object of mass M is tied to a string of l and revolve in a horizont

1.	An object of mass M is tied to a string of l and revolve in a horizontal circle .If length is reduced by `l//2`, then period isA. `T//sqrt2`B. `2sqrt2 T`C. `T//4`D. `2 T`
Answer» Correct Answer - C `omega =(2 pi)/(T)=(v)/(l)` Accounding to the law of conservation of angular momentum , `m_(1)v_(1)r_(1)=m_(2)v_(2)r_(2)` `therefore r_(1)^(2) omega _(1)=r_(2)^(2)omega _(2)implies (r_(1)^(2))/(T_(1))=r_(2)^(2)/(T_(2))` `therefore T_(2)=((r_(2)^(2))/r_(1)^(2))T_(1)((l^(2)//4)/(l^(2)))T=(T)/(4)`.

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An object of mass M is tied to a string of l and revolve in a horizontal circle .If length is reduced by `l//2`, then period isA. `T//sqrt2`B. `2sqrt2 T`C. `T//4`D. `2 T`

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